Waec 2017 Mathematic Essay, Obj Answers – May/June Expo

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2017 WAEC EXAM EXPO: 2017 2017 WAEC EXAM EXPO: MATHEMATIC QUESTIONS AND ANSWERS Free Expo Answers – 2017

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*2017 WAEC CERTIFIED MATHEMATICS OBJECTIVES*

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SECTION A ANS ALL

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1a)

(y-1)log4^10= ylog16^10

log4^10 (y-1)= log16^y10

4^(y-1)=16y

4^y-1=4^2y

y-1=2y

-1=2y=y

-1=y

y= -y

1b)

let the actual time for 5km/hr be t

for 4km/hr=30mint + t

4km/hr=0.5 + t

distance = 4(0.5+t)

=2*4t

for 5km/hr, time= t

distance =5t

1+4t=5t

t=2hrs

actual distance = 5*2=10km

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2a)

2/3(3x-5)-3/5(2x-3)=3/1

L C M =15

10(3x-5)-9(2x-3)=45

30x-50-18x+27=45

30x-18x=45+50-27

12x-23=45

12x=45+23

12x=68

x=68/12

x=34/6

x=17/3

2b)

U’aS=180-(n+88)

=180-n-88=92-n

also, u’TQ=18m

80degree + 92-n+180-m=180degree

80+92+180-n-m=180degree

352-n-m=180degree

-n-m=180-352

-n-m=-172

+(n+m)= +172

m+n=172dgree

==================

3a)

Tan 23.6° = h/50

Cross multiply

Tan 23.6° x h/50

h = 50 tan 23.6°

= 21.844m‎

3b)

Area of

2y-34=120 2y=154 y=154/2 y=77 number of customers who bought shoe = y+11 77+11=88 5c) n(bag)=77customers probability =77/120 =0.642 ===================== SECTION B ANS 5 QUESTIONS ONLY ===================== 10a) Sin x = 5/13 Using pythagoras rule M^2 = 13^2 - 5^2 (^ means Raise to power) M^2 = 169 - 25 M ^2 = 144 M = √144 M = 12 Hence: Cos x - 2sin x / 2tan x 12/13 - 2(5/13) / 2(5/12) ‎= 12/13 - 10/23 / 5/6 FIND LCM = 12 - 10/13 / 5/6 = 12/65 10bi) Considering < LMB /MB/^2. = 12^2 - 9.6^2 /MB/^2 = 51.84 /MB/ = √51.84 /MB/ = 7.2m From < AML /LA/^2 = 2.8^2 + 9.6^2 /LA/ ^2 = 100 /LA/ = √100 /LA/ = 10m 10bii) Let the angle be. θ From
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X = 1,2,3,4,5 F = 5,2,3,8,5 Cum Freq= 5,7,10,18,23 Q1 = (N+1/4) = (23+1/4) = 6 Q3 = (3N + 1/4) = (3*23+1/4) = 18 Inter quarter range = Q3 - Q1 =. 18-6 = 12 8bii) Pr. (at least 4 mark) = 8+3+2+5/23 = 18/23‎ ================ 12a) 3y^2-5y+2=0 y^2 - 5/3y + 2/3=0 y^2-5/3y=-2/3 y^2-5/3y+(^-5/6)^2=(-^5/6)^2-2/3 (y-5/6)^2=25/36-2/3 (y-5/6)^2=25/-24/36 (y-5/6)^2=1/36 (y-5/6)=+sqr1/36 y=5/6+1/6 y=5+1/6 or 5-1/6 y=6/6 or 2/3 y=1 or 2/3 12b) given M N = [2,3 1,4] hence [1,4 2,3] * [m,n x,y] =[2,3 1,4] [m+2n, x*2y] [4m+3n, 4x+5y] = [2,3, 1,4] therefore m+2n=2------(i) 4m+3n=3------(ii) from ------(i) m=2-2n 4(2-2n)+3n=3 8-8n+3n=3 8-5n=3 8-3=5n 5=5n n=1 hence m=2-2(1) M=0 also x+2y=1------(i) 4x+3y=4------(ii) from ------(iii) x=1-2y 4(1-2y)+3y=4 4-8y+3y=4 y=0 therefore x=1-2(0) x=1 this N=[i i] ================ 11a) 8 students finished 12 tanks in 2/3 (60) mins = 40 mins 4 student wil finish X tanks in 1/3 (60)min = 20mins X = 4x20x12/8x40 = 3tanks 11b) L(AB) = 200m |ON| = 12cm r2 = (AN)2 + (ON )2 r2 = (10)2 +(12)2 r2 = 100 + 144 r2 = 244 r = Sqr 244 r = 15.6CM 11bii) L(AB) = 2r sin 0/2 20 = 2 (15.6) sin 0/2 20 = 31.2 sin 0/2 sin0/2 = 20/31.2 sin0/2 = 0.6410 0/2 = sin -1 (0.6410) 0/2 = 39.87 0 = 2 (39.87) 0 = 79.74 = 79.7' (1 d.p ) 11bii) p 2r + 0/360 x 2TTr = 2 (15.6 ) + 79.7/360 x 2x 3 x42x15.6 =31.2 + 21.7 = 52.9 cm NECO/NABTEB ENQUIRIES only, Call 09033696908

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