## 2017 WAEC EXAM EXPO: 2017 2017 WAEC EXAM EXPO: MATHEMATIC QUESTIONS AND ANSWERS Free Expo Answers – 2017

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*2017 WAEC CERTIFIED MATHEMATICS OBJECTIVES*

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SECTION A ANS ALL

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1a)

(y-1)log4^10= ylog16^10

log4^10 (y-1)= log16^y10

4^(y-1)=16y

4^y-1=4^2y

y-1=2y

-1=2y=y

-1=y

y= -y

1b)

let the actual time for 5km/hr be t

for 4km/hr=30mint + t

4km/hr=0.5 + t

distance = 4(0.5+t)

=2*4t

for 5km/hr, time= t

distance =5t

1+4t=5t

t=2hrs

actual distance = 5*2=10km

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2a)

2/3(3x-5)-3/5(2x-3)=3/1

L C M =15

10(3x-5)-9(2x-3)=45

30x-50-18x+27=45

30x-18x=45+50-27

12x-23=45

12x=45+23

12x=68

x=68/12

x=34/6

x=17/3

2b)

U’aS=180-(n+88)

=180-n-88=92-n

also, u’TQ=18m

80degree + 92-n+180-m=180degree

80+92+180-n-m=180degree

352-n-m=180degree

-n-m=180-352

-n-m=-172

+(n+m)= +172

m+n=172dgree

==================

3a)

Tan 23.6° = h/50

Cross multiply

Tan 23.6° x h/50

h = 50 tan 23.6°

= 21.844m

3b)

Area of

2y-34=120
2y=154
y=154/2
y=77
number of customers who bought shoe = y+11
77+11=88
5c)
n(bag)=77customers
probability =77/120
=0.642
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SECTION B ANS 5 QUESTIONS ONLY
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10a)
Sin x = 5/13
Using pythagoras rule
M^2 = 13^2 - 5^2 (^ means Raise to power)
M^2 = 169 - 25
M ^2 = 144
M = √144
M = 12
Hence:
Cos x - 2sin x / 2tan x
12/13 - 2(5/13) / 2(5/12)
= 12/13 - 10/23 / 5/6
FIND LCM
= 12 - 10/13 / 5/6
= 12/65
10bi)
Considering < LMB
/MB/^2. = 12^2 - 9.6^2
/MB/^2 = 51.84
/MB/ = √51.84
/MB/ = 7.2m
From < AML
/LA/^2 = 2.8^2 + 9.6^2
/LA/ ^2 = 100
/LA/ = √100
/LA/ = 10m
10bii)
Let the angle be. θ
From ALSO READ: WASSCE 2017 For Private Candidates Registration Deadline Extendedu

X = 1,2,3,4,5
F = 5,2,3,8,5
Cum Freq= 5,7,10,18,23
Q1 = (N+1/4) = (23+1/4)
= 6
Q3 = (3N + 1/4) = (3*23+1/4)
= 18
Inter quarter range = Q3 - Q1
=. 18-6
= 12
8bii)
Pr. (at least 4 mark)
= 8+3+2+5/23
= 18/23
================
12a)
3y^2-5y+2=0
y^2 - 5/3y + 2/3=0
y^2-5/3y=-2/3
y^2-5/3y+(^-5/6)^2=(-^5/6)^2-2/3
(y-5/6)^2=25/36-2/3
(y-5/6)^2=25/-24/36
(y-5/6)^2=1/36
(y-5/6)=+sqr1/36
y=5/6+1/6
y=5+1/6 or 5-1/6
y=6/6 or 2/3
y=1 or 2/3
12b)
given
M N = [2,3 1,4]
hence
[1,4 2,3] * [m,n x,y] =[2,3 1,4]
[m+2n, x*2y]
[4m+3n, 4x+5y] = [2,3, 1,4]
therefore
m+2n=2------(i)
4m+3n=3------(ii)
from ------(i)
m=2-2n
4(2-2n)+3n=3
8-8n+3n=3
8-5n=3
8-3=5n
5=5n
n=1
hence
m=2-2(1)
M=0
also
x+2y=1------(i)
4x+3y=4------(ii)
from ------(iii)
x=1-2y
4(1-2y)+3y=4
4-8y+3y=4
y=0
therefore x=1-2(0)
x=1
this N=[i i]
================
11a)
8 students finished
12 tanks in 2/3 (60) mins
= 40 mins
4 student wil finish
X tanks in 1/3 (60)min
= 20mins
X = 4x20x12/8x40
= 3tanks
11b)
L(AB) = 200m |ON| = 12cm
r2 = (AN)2 + (ON )2
r2 = (10)2 +(12)2
r2 = 100 + 144
r2 = 244
r = Sqr 244
r = 15.6CM
11bii)
L(AB) = 2r sin 0/2
20 = 2 (15.6) sin 0/2
20 = 31.2 sin 0/2
sin0/2 = 20/31.2
sin0/2 = 0.6410
0/2 = sin -1 (0.6410)
0/2 = 39.87
0 = 2 (39.87)
0 = 79.74
= 79.7' (1 d.p )
11bii)
p 2r + 0/360 x 2TTr
= 2 (15.6 ) + 79.7/360 x 2x 3 x42x15.6
=31.2 + 21.7
= 52.9 cm

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